Agoblet contains 333 red balls, 222 green balls, and 666 blue balls. if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

Step-by-step explanation:

A goblet contains 3 red balls, 2 green balls and 6 blue balls.

Total balls = 3 + 2 + 6 = 11 balls

we choose a ball and then another ball without putting the first one back.

The probability that the first ball will be red = =

Second event is done without replacing the first ball so total ball will be 10

The probability that the second ball will be blue = = =

P = × =

The probability that the first ball will be red and the second ball will be blue is

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation: