The surface area of two hemispheres are in the ratio 64: 121. Find the ratio of
their radii

R : 8 , R: 11

explaination:

CSA OF HEMISPHERE IS  ; 2r2

CSA  of 1st hemisphere is in ratio of 2nd one

2r2:2r2

then 2 and pi will be cancelled rest is  '' r ''square.

then find the squares of their 64 and 121

which 64= 8

121= 11

you need a common difference between consecutive terms to be constant, like 1,2,3,4 or 2,4,6,8, or 1,3,6,9

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: