Find the area of parallelogram ABCD given m∠A = 30° and the following measures. AD = in.; AB = 8 in. A= 32 in.²
32√3 in.²
16√3 in.²'

Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3

Angle A =30

To find the area of the parallelogram

We have area of parallelogram = base x height

Here base can be taken as side AB = 6 ft

Height = perpendicular distance of AB from vertex X

= AX sin A

= 3√3sin30

=1.5√3

Hence area =6(1.5√3)=9√3ft^2

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16√3 in.²'

Step-by-step explanation:

Hope this helps, sorry for answering late.

x=12 units bd= 10 units

step-by-step explanation:

answer: idk

step-by-step explanation: