Please help due by tonight.

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y = 1/2x^2 - 2x - 1

Step-by-step explanation:

Vertex(2, - 3)

Equation of Parabola (In vertex form): y = a(x - h)^2 + k,

                                                               y = a(x - 2)^2 - 3

Substitute given point (0, -1) and solve for a:

y = a(x - 2)^2 - 3,

-1 = a(0 - 2)^2 - 3,

a = 1/2

Equation: y = 1/2(x - 2)^2 - 3 = 1/2(x^2 - 4x + 4) - 3 = 1/2x^2 - 2x + 2 - 3 = 1/2x^2 - 2x - 1,

y = 1/2x^2 - 2x - 1: Option C

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.