The equilibrium constant for A + 2B → 3C is 2.1 * 10^-6 Determine the equilibrium constant for 2A + 4B → 6C.
a- 4.2 * 10^-6
b- 4.4 * 10^-12
c- 2.3 *10^11
d- 1.8 *10^-11
e- None of these

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

Thus, the equilibrium constant of the second reaction turns out:

Therefore, the answer is b- 4.4 * 10^-12.

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