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Mathematics, 08.11.2019 03:31 vanessajimenez361

Erica solved the equation βˆ’5x βˆ’ 25 = 78; her work is shown below. identify the error and where it was made.

βˆ’5x βˆ’ 25 = 78
step 1: βˆ’5x βˆ’ 25 βˆ’ 25 = 78 βˆ’ 25
step 2: βˆ’5x = 53
step 3: negative five times x over negative five = fifty-three over negative five
step 4: x = negative fifty-three over five

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Erica solved the equation βˆ’5x βˆ’ 25 = 78; her work is shown below. identify the error and where it w...
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