So I have a question. Its a really good question. I'm not sure you'll get it though. Okay so my question is if a train leaves a station at 12 o'clock and moves at a constant speed of 90 mph and another train leaves a different station 2000 miles away in the opposite direction at 2 o'clock traveling at 80 mph. When will both trains cross each other?

Step-by-step explanation:

Train 1 will travel for 2 hours before the second train leaves.

The distance at 2 o'clock is reduced by 2*90 = 180 miles and now is:

Let the trains spend x hours before crossing, then we have following equation for the distance:

The trains will cross at:

The time when trains cross each other will be approximately 12:42

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.