solution of nitric acid is 60% with the specific gravity 1.15 calculate the volume of the seed required to prepare 250 ml semi normal solution

This dilution problem uses the equation

M

a

V

a

=

M

b

V

b

M

a

= 6.77M - the initial molarity (concentration)

V

a

= 15.00 mL - the initial volume

M

b

= 1.50 M - the desired molarity (concentration)

V

b

= (15.00 + x mL) - the volume of the desired solution

(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )

101.55 M mL= 22.5 M mL + 1.50x M

101.55 M mL - 22.5 M mL = 1.50x M

79.05 M mL = 1.50 M

79.05 M mL / 1.50 M = x

52.7 mL = x

59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.

Explanation:

what is the question?