A pet store is selling dogs for $140 and cats for $70. If 28 pets were sold and they made $3,360. Write a system of equations that matches the situation

A system of equations that matches the situation is:

1) d + c = 28Equation 1

2)140d + 70c = 3360Equation 2

This question has to do with Algebraic equations.

Let's represent

Number of dogs = d

Number of cats  = c

A pet store is selling dogs for $140 and cats for $70. If 28 pets were sold and they made $3,360.

We have two algebraic systems of equations for the above statements

1) d + c = 28Equation 1

2) $140 x d + $70 x c = $3,360

140d + 70c = 3360Equation 2

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x+y=28

70x+140y=3360

8 cats, 20 dogs were sold

Step-by-step explanation:

Let x=cats y=dogs

We know that a total of 28 pets were sold which means that

x+y=28

We also know that they made 3360 which means that

70x+140y=3360

It doesn't really say if you need to solve this but I will anyways

We use the first equation (x+y=28) and subtract 28 and y from both sides to get

x-28= -y we can then divide both sides by -1 so y can be a positive

-x+28=y

This is what y equals in terms of x and so we can plug this in for y in the second equation

70x+140(-x+28)=3360

Distribute the 140 and get

70x-140x+3920=3360

Add like terms and subtract 3920 to get

-70x=-560

divide both sides by -70 and get

x=8

We now know that 8 cats were sold and can plug this value into any equation to solve for y ( I will be using the first one because that's easiest)

8+y=28

subtract 8 and get

y=20

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