An isosceles right triangle has a hypotenuse length that can be modeled with the function h(x) = x^2. The combined length of the legs can be modeled with the function L(x) = 2x.
Which function, p(x), can be used to find the perimeter of the triangle?
O p(x) = {V2 + x
O p(x) = x^2 + 2x
O p(x) = x2 + 4x
O p(x) = 2xV2 + 4x

i'm pretty sure it's 477,585,296, but perhaps my math is incorrect.

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

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step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: