Find the mistake and correct it

i believe its the second part thats wrong  

Step-by-step explanation:

1 Distribute

−5(−2+10)=20

10−50=20

2 Add 50 to both sides of the equation

10−50=20

10−50+50=20+50

3 Simplify

Add the numbers

10x−50+50=20+50

10=20+50

Add the numbers

10x =20 + 50

10x=10

4 Divide both sides of the equation by the same term

10x = 70

10x   70

=

10      10

5 Simplify

Cancel terms that are in both the numerator and denominator

10x   70

=

10      10

      70

x  =

       10

        70

x  =

       10  

x=7

Solution

= 7

hopes it helps and list brain list plz

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

b

step-by-step explanation: