The perimeter of a rectangular garden is 72 feet. If the width is 8 feet less than the length, write a system of equations involving the length and width, L and W, and solve it to find the dimensions of the rectangle.

width -w

length l= 2*w+5

perimeter P=2w+2l, 52=2w+2l

system of equations:

52=2w+2l  > 26 =w+l  (1)

l= 2*w+5    (2)

substitute  value of l from second equation into the 1st

26=w+2w+5

26=3w+5

21=3w

w=7

l=2w+5,  l=2*7+5, l=19

system

52=2w+2l

l= 2*w+5  

length 19 ft, width 7 ft

Step-by-step explanation:

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please mark brainliest

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

srry idk

step-by-step explanation: