Calculate the clothing insulation (CLO) rating required to keep an average-sized man (surface area = 19.565 ft2) warm, while performing callisthenic exercises outside for 1 hour at a metabolic rate of 4.0 MET, where the ambient temperature is 41 degrees F, and the wind speed is negligible? The standard amount of insulation required to keep a resting person warm in a windless room at 70°F is equal to one CLO. The desired mean maintained normal temperature of skin is about 91°F, and 1 CLO = {[0.88 × Δ∘F × ft2 × hr.] / BTU}

the clothing insulation (CLO) rating required is 202.95

Step-by-step explanation:

Given the data in the question;

1 MET for an average sized man of surface area 19.565 ft²

1met = 18.48[ BTU/hr.ft²]

According to Ques;

1 CLO = 0.88[ Δ°F.hr.ft² / BTU ]  

so

1 CLO = 0.88[ Δ°F×18.48 / 1MET ]  

our Δ°F = temperature of the skin - ambient temperature = 91°F - 41°F = 50°F

MET = 4.0

therefore required CLO will be

CLO = 0.88[ 50 × 18.48 / 4.0 ]  

CLO = 0.88 × 230.625

CLO = 202.95

Therefore, the clothing insulation (CLO) rating required is 202.95

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