An investor bought a number of shares of stock for $1600 after Priess dropped by $10 per share she sold all but four of her shares for $1120 how many shares that she originally by?

She originally bought either 20 or 32 shares

Step-by-step explanation:

An investor bought a number of shares of stock for $1600 after Price dropped by $10 per share she sold all but four of her shares for $1120 how many shares that she originally by?

Let the number of shares she bought be represented by 1600/x

This is calculated as:

1600/x  = 1120/x + 10  + 4

Multiply through by (x)(x - 10)

1600(x-10) = 1120(x) + 4(x)(x - 10)

1600x - 16000 = 1120x + 4x² - 40x

Collect like terms

4x² + 1120x - 1600x - 40x +16000 = 0

4x² - 520x + 16000 = 0

Using the Almighty formula method

= -b ± √b²- 4ac/2a

a = 4, b = -520 , c = 16,000

Hence:

= -(-520) ± √-520² - 4 × 4 × 16000/2 × 4

= 520 ± √14400/8

= 520 ± 120/8

520 - 120/8

= 400/8

= 50

520 ± 120/8

= 520 + 120/8

= 640/8

= 80

Since we have:

1600/x

When x = 50

= 1600/50

= 32

When x = 80

= 1600/80

= 20

Therefore, she originally bought either 20 or 32 shares

i think is g(1)=-1.

hope that i can