If you are adding (6a – 3) and (-3a + 6), which of the following choices shows like terms correctly grouped? (1 point) TE O (6a - 3a) + (-3+6) It Ite O (6a + 6) + (-3a – 3) Ite o (6a - 3a) - 3 + 6 0 (6a + 3a) + (-3+6)

9514 1404 393

  (a)  (6a - 3a) + (-3+6)

Step-by-step explanation:

Assuming "properly grouped" means that parentheses are placed around each group of terms, the appropriate choice is the one that groups 'a' terms and constant terms:

  (6a - 3a) + (-3 + 6)

21.4 i did it already for s1

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.