Find the area of the quadrilateral in the figure.

a. 22.25
b. 19.64
c. 15.25
d. 13.64

(B)

Step-by-step explanation:

If we re draw the given figure which is not so scale, we get that ABC is right angled triangle as:

which holds the Pythagoras theorem, thus ABC is right angle triangle which is right angled at B.

Now, it can also be seen from the drawn figure, that ADC is an isosceles triangle, therefore

Area of triangle ABC=

=

=

Now, Area of triangle ADC is given by heron's formula that is:

A=

and s=

Thus, s=

Area=

=

=

=

Now, area of the Quadrilateral ABCD is =Area of triangle ABC+ area of triangle ADC

=

=

therefore, area of the Quadrilateral ABCD is 19.64 sq units.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>