There are 3 people in a room, and we are curious whether two of them have their birthday in the same month. We record the triplet that describes the month of birthday for each person. E. g. (Oct, Jan, Jul) is one possible triplet/outcome. (Since each month applies to a specific person, (Oct, Jan, Jul) is not the same as (Jan, Jul, Oct) and so order is important.) a. How many possible outcomes are there

The possible outcomes are 1728.

Step-by-step explanation:

Consider the provided information.

We know that there are 12 months in a year and we have 3 people in a room.

As the order is important it means for each person we have 12 choices of the months.

The possible outcomes are:

Hence, the possible outcomes are 1728.

show us the graphs dude

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft