Given f(x) = 3x2 + x and g(x) = 2x. What is lim off(x))? *--4
44
88
104
188
NEED HELP ASAP 30 POINTS

Step-by-step explanation:

Given the functions

f(x) = 3x² + x and g(x) = 2x

We are to find g(f(x))(-4)

First get g(f(x))

g(f(x)) = g(3x²+x)

Substitute x in g(x) with 3x²+x to have:

g(3x²+x) = 2((3x²+x))

g(3x²+x) = 6x² + 2x

Substitute  = -4 into the result

g(f(x) (-4)) = 6(-4)² + 2(-4)

g(f(x) (-4)) = 6(16)-8

g(f(x) (-4)) = 96 - 8

g(f(x) (-4)) = 88

Hence the required answer is 88

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions