Mathematics, 02.01.2021 23:50 bri663

Determine any data values that are missing from the table, assuming that the data represent a linear function. a. Missing x:13 Missing y:20
b. Missing x:13 Missing y:19
c. Missing x:11 Missing y:20
d. Missing x:11 Missing y:19

Determine any data values that are missing from the table, assuming that the data represent a linea

Answers: 2

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Answer from: sheena33

d. Missing x:11 Missing y:19

Step-by-step explanation:

It can be determined that the function is:

y = 0.5x + 12.5

So missing x is:

18 = 0.5x + 12.5 ⇒ 0.5x = 5.5 ⇒ x = 11

Missing y is:

y = 13*0.5 + 12.5 = 19

Missing numbers are:

x= 11 and y = 19

Correct choice is d.

Answer from: oreojtlover6330

FIRST METHOD

Missing x = 11Missing y = 19

Step-by-step explanation:

Given the table

x y

7 16

9 17

Missing x 18

13 Missing y

From the table, it is clear that y-values are incremented by 1 unit and the x-values are incremented by 2 units.

i.e.

y = 17-16 = 1

y = 18-17 = 1

as 19-18 = 1

Thus,

Thus, the value of Missing y = 19

also the x-values increment by 2.

i.e.

x = 9-7 = 2

as x = 11 - 9 = 2

Thus, Missing x = 11

Therefore,

Missing x = 11Missing y = 19

2ND METHOD

Given that the table represents a linear function, so the function is a straight line.

Taking two points

(7, 16)(9, 17)

Finding the slope between (7, 16) and (9, 17)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(7,\:16\right),\:\left(x_2,\:y_2\right)=\left(9,\:17\right)$

$m=\frac{17-16}{9-7}$

$m=\frac{1}{2}$

Using the point-slope form to determine the linear equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 1/2 and the point (7, 16)

$y-y_1=m\left(x-x_1\right)$

$y-16=\frac{1}{2}\left(x-7\right)$

Add 16 to both sides

$y-16+16=\frac{1}{2}\left(x-7\right)+16$

$y=\frac{1}{2}x+\frac{25}{2}$

Thus, the equation of the linear equation is:

$y=\frac{1}{2}x+\frac{25}{2}$

Now substituting y = 18 in the equation

$18=\frac{1}{2}x+\frac{25}{2}$

Switch sides

$\frac{1}{2}x+\frac{25}{2}=18$

subtract 25/2 from both sides

$\frac{1}{2}x+\frac{25}{2}-\frac{25}{2}=18-\frac{25}{2}$

$\frac{1}{2}x=\frac{11}{2}$

x=11

Thus, the value of missing x = 11 when y = 18

Now substituting x = 13 in the equation

$y=\frac{1}{2}\left(13\right)+\frac{25}{2}$

$y=\frac{13}{2}+\frac{25}{2}$

$y=\frac{13+25}{2}$

$y=\frac{38}{2}$

y = 19

Thus, the value of missing y = 19 when x = 13

Hence, we conclude that:

The value of missing x = 11The value of missing y = 19

Hence, option D is true.

Answer from: Quest

I’m not positive but i think it’s none of your buisness

Answer from: Quest

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” is $(\frac{n}{2}+12)-4$ when n=4,we substitute 4 whetever we see n to get, $(\frac{4}{2}+12)-4$ we simplify to obtain, $=(2+12)-4$ we further simplify to get, $=14-4=10$ therefore the correct answer is c.

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