Your search - construct a right triangle ABC in which base ABC in which baseBC =4.8cm, AngleB=90 degree and AC=6.2cm.

AB = 3.9CM ; A = 51° ; C = 39°

Step-by-step explanation:

Base BC = 4.8cm

AC = 6.2cm

Angle B = 90°

Using trigonometry, the length of AB can be obtained thus :

AB^2 = AC^2 - BC^2

AB^2 = 6.2^2 - 4.8^2

AB^2 = 38.44 - 23.04

AB^2 = 15.4

AB = sqrt(15.4)

AB = 3.92 cm

Angle A :

Using :

Sinα = opposite / hypotenus

Sinα = 4.8 / 6.2

Sinα = 0.7741935

α = sin^-1 (0.7741935)

α = 50.73

A = 51° (approximately)

Angle C ;

(A + B + C) = 180 (Sum of angles in a triangle)

51 + 90 + C = 180

141 + C = 180

C = 180 - 141

C = 39°

the 3rd option is right

step-by-step explanation:

i am unable to solve this problem

step-by-step explanation: