Cut out the shapes of NETS of Cube, Cuboid and Cylinder as per the dimensions given below and find its Total Surface Area and Lateral Surface Area Dimensions of Cube = 5cm x 5cm x 5cm Dimensions of Cuboid = Length=10cm, Breadth=5cm, Height = 4cm Dimensions of Cylinder= Diameter 7cm and height 10cm

a. i. 150 cm³ ii. 150 cm³

b. i. 220 cm³ ii. 120 cm³

c. i. 297 cm² ii. 220 cm²

Step-by-step explanation:

a. For the cube

Dimensions of Cube = 5cm x 5cm x 5cm

Length of side = 5 cm

i. Total surface area A = 6L² where L = length of side = 5 cm

So, A = 6 × (5 cm)²

= 6 × 25 cm³

= 150 cm³

ii. Lateral surface area A' = 4L²

= 4 × (5cm)²

= 4 × 25 cm²

= 100 cm²

b. For the cuboid

Dimensions of Cuboid = Length, l = 10cm, Breadth, b = 5cm, Height, h = 4cm

i. Total surface area A = 2(lb + lh + hb)

= 2(10 cm × 5 cm + 10 cm × 4 cm + 4 cm × 5 cm)

= 2(50 cm² + 40 cm² + 20 cm²)

= 2(110 cm²)

= 220 cm²

ii. Lateral surface area A' = 2(lh + hb)

= 2h(l + b)

= 2 × 4 cm (10 cm + 5 cm)

= 8 cm × 15 cm

= 120 cm²

c. For the cylinder

Dimensions of Cylinder = Diameter, d = 7cm and height, h = 10cm

i. Total surface area, A = 2πr(r + h) where r = radius = d/2

A = πd(d/2 + h)

= 22/7 × 7 cm(7 cm/2 + 10 cm)  

= 22cm(3.5 cm + 10 cm)

= 22cm(13.5 cm)

=  297 cm²

ii. Lateral surface area A = 2πrh

= πdh

= 22/7 × 7 cm × 10 cm

= 22 cm × 10 cm

= 220 cm²

what