In isosceles triangle ABC the segment BD with D a point on AC is the median to the base AC. Find BD if the perimeter of ABC is 50m and the perimeter of ABD is 40m

Given:

In isosceles triangle ABC, consider AB=BC and the segment BD with D a point on AC is the median to the base AC.

Perimeter of ABC is 50m and the perimeter of ABD is 40m.

To find:

The length of BD.

Solution:

In isosceles triangle ABC the segment BD with D a point on AC is the median to the base AC.

          ...(i)

        ...(ii)

Perimeter of ABC is 50m.

     [Using (i) and (ii)]

Divide both sides by 2.

       ...(iii)

Now, perimeter of ABD is 40m.

        [Using (iii)]

Therefore, the length of BD is 15m.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation: