Matthew dropped a tennis ball off the roof of 100 foot tall building. The objects height (y) is modeled by the equation below. At what time (t) does the ball hit the ground? Round your answer to the nearest tenth

2 seconds later

Step-by-step explanation:

Since the required equation is lacking, let the equation modeled by the height be expressed as y = -16t² + 64

The ball hits the ground at y =0. Substitute y = 0 into the expression and find t;

Since y = -16t² + 64

0 =  -16t² + 64

16t² = 64

t² = 64/16

t² = 4

t = ±√4

t = 2 and -2

Time cannot be negative, hence the ball hits the ground 2 seconds later.

Note that the equation used was assumed. Similar solution can be applied for any given equation.

50=33x+22

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b