A researcher's measure of species diversity is made from water samples taken from two independent locations. The research finds the 95% confidence interval for the difference between species diversity in the two locations to be 0.223 space less than space mu subscript 1 minus mu subscript 2 less than 1.361. Based on part the researcher's confidence interval, is it reasonable to conclude that species diversity in location 1 is greater than species diversity in location 2

It is  reasonable to conclude that species diversity in location 1 is greater than species diversity in location 2.

Step-by-step explanation:

From the question we are told that

      The   95% confidence interval for the difference between species diversity in the two locations  is  

Now this 95%  confidence interval tell us that there a 95%  confidence that the true difference between species diversity in the two locations is within the interval

For the value of the 95% confidence interval given we see that both  the upper limit and the lower limit is greater than zero which tell us that the true difference will also be greater than zero

Hence

  it is  reasonable to conclude that species diversity in location 1 is greater than species diversity in location 2

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9