Line JK passes through J (-3,11) and K (1, -3) what is the equation of line JK in point slope form? A. Y - 11 = 7/2(x-3)
B. Y + 3 = 7/2(x-1)
C. Y - 11 = -7/2(x+3)
D. Y - 3 = -7/2(x-1)

pls help

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

positive

step-by-step explanation:

the quadrant is facing upwards