Find an equation of the plane through (-1,4,-3) and perpendicular to the line x-2=t , y+3=t , z=-t

  x + y -z = 6

Step-by-step explanation:

The equation of the line can be rewritten as ...

  (x, y, z) = (2, -3, 0) +t(1, 1, -1)

The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.

  x + y - z = (-1) +(4) -(-3)

  x + y - z = 6 . . . . equation of the plane

i dont know what you want me to answer for this but im guessing 2: 11?

i believe it is the square root of 122 because when you turn it on it's side, to where the 5 inches is on the bottom, it looks like it is the same length.