A man and his bike are 95 kg. His instantaneous speed at one point is 14m/s. The next time his speed is checked he is going 28m/s. If the second speed was taken 7 seconds later, what force must the man have given his bike to change the speed? What was the bicyclist’s final momentum?

you would need to know all the numbers that are on there

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4