Triangle has sides 7 inches, 7.5 inches, and x inches. What is the range of possible lengths for side x, in inches? A. 0.5 x>14.5

C. 0.5≥x≥14.5

D.0.5≤x≤14.5

The  range of possible lengths for side x, in inches is 0.5 < x < 14.5

Using the triangular law which states that the sum of any two sides must be greater than the third.

x + y > z

y + z > x

x + z > y

From the equations above;

x > z - y and y + z > x

z-y < x < y+z

Let y = 7 and z = 7.5

7.5 - 7 < x < 7 + 7.5

0.5 < x < 14.5

Hence the  range of possible lengths for side x, in inches is 0.5 < x < 14.5

Learn more eon triangular law here: link

0.5 < x < 14.5

Step-by-step explanation:

Triangle Inequality Theorem

Let y and z be two of the side lengths of a triangle. The length of the third side x cannot be any number. It must satisfy all the following restrictions:

x + y > z

x + z > y

y + z > x

Combining those inequalities, and provided y>z, the third size must satisfy:

y - z < x < y + z

We are given two of the triangle side lengths as y=7.5 and z=7, thus the third side length (x) can be in the range:

7.5 - 7 < x < 7.5 + 7

0.5 < x < 14.5

Note: The latter is the correct answer but none of the choices is accurate. Choice D is closer to the correct answer but the endpoints cannot be included.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

78.59 is the mean

step-by-step explanation: