7(5a − 4) = 14 − 8a + 1

a = 1

Step-by-step explanation:

7(5a − 4) = 14 − 8a + 1

Distributive property ( multiply what is inside the parenthesis by 7)

7 * 5a - 7 * 4 = 14 - 8a + 1

35a - 28 = 14 - 8a + 1

Combine like terms

35a - 28 = 15 - 8a

Add 8a on both sides

35a + 8a - 28 = 15 - 8a + 8a

43a - 28 = 15

Add 28 on both sides

43a - 28 + 28 = 15 + 28

43a = 43

Divide by 43 on both sides to isolate the variable

43a/43 = 43/43

a = 1

Check

7(5a − 4) = 14 − 8a + 1

Just substitute the "a" with "1"

7(5 * 1 − 4) = 14 − 8 * 1 + 1

35 - 28 = 14 - 8 + 1

7 = 7 CORRECT

Hope this helped!

have a day!

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.