What is the equation of the line that passes through the point (-3, 2) and
has a slope of –2/3

y = -2/3 (x+3) + 2

Step-by-step explanation:

use the point-slope form equation: y - y1 = m (x - x1)

plug in the point (-3,2) and slope -2/3 into the equation:

y - 2 = -2/3 [x - (-3)]

you can simplify it:

y - 2 = -2/3 (x+3)

and you can also put it in terms of y:

y = -2/3 (x+3) + 2

first one because it can't have a fraction in it

step-by-step explanation: