Mary worked from monday to saturday last week and bought lunch in the companys restaurant everyday. Her lunches cost a different amount everyday. Each lunch cost cost a multiple of 20 cents. The most expensive lunch of the week cost $7.60 and the cheapest costs $4.40. Fridays lunch costs exactly 1 1/2 times as much as wednesdays lunch. Tuesdays lunch costs $1.20 more than thursdays lunch.

What is the minimum total that Mary’s six lunches last week could have cost?

What is the maximum total that Mary’s six lunches last week could have cost?

nswer: a   y-axis

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages