A doctor estimates that a particular patient is losing bone density at a rate of 3% annuallythe form f(x)=ab^ x , where f(x) represents the bone density after x years ?

The question above is incomplete

Complete Question

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually. The patient currently has a bone density of 1,500 kg/mg³. The doctor writes an exponential function to represent the situation. Which values should the doctor use for a and b in a function written in the form f(x) = ab^x, where f(x) represents the bone density after x years?

a = 1500

b = 0.97

f(x) = ab^x

f(x) = 1500(0.97)^x

f(x) = 1500 × 0.97^x

Step-by-step explanation:

We are to find a and b

This question has to do with exponential decay.

This is written as

y = a(1 - r)^x

f(x) = ab^x

r = rate of exponential decay

f(x) = y

a = a

b^x = (1 - r)^x

a = current bone density of the patient = 1500kg/m³

b = (1 - r)

r = 3% = 0.03

b = (1 - 0.03)

b = 0.97

Therefore,

a = 1500

b = 0.97

Hence:

f(x) = ab^x

f(x) = 1500(0.97)^x

f(x) = 1500 × 0.97^x

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.