The sum of two real numbers is 8 and their product is 14. What is the sum of their reciprocals?

Step-by-step explanation:Let our two numbers be  a  and  b . Then we can see that  a+b=8  and  ab=15 . Now consider

(a+b)3=a3+3a2b+3ab2+b3  by the binomial expansion. Now we have all the information to solve this, observe since  a+b=8  and  ab=15 . We have

(8)3=a3+3ab(a)+3ab(b)+b3  

a3+b3+3ab(a)+3ab(b)=83  

a3+b3+3ab(a+b)=83  

a3+b3=83−3ab(a+b)  

a3+b3=83−3(15)(8)=512−360=152  

You can also observe that  3  and  5  fulfill those conditions so, then  33+53=27+125=152 . Which is our result.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this