Solve for x.
10 = x + 5 + x

A. 5
B. 10
C. 5/2
D. no solution

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the k side

step-by-step explanation:

plese mark mde brainliest!

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof

20days louise can read300 pg

step-by-step explanation:

1 day 15 pg 300: 15= 20

x day 300 pg