Find a so that the point (-1,3) is on the graph of f(x) = ax^2 + 2

The points on a graph are the true values of the graph

The value of a is 1

The equation is given as:

At point (-1,3), the equation becomes

Evaluate the exponent

This gives

Subtract 2 from both sides

Hence, the value of a is 1

Read more about points and graphs at:

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a = 1

Step-by-step explanation:

Plug in the point into the equation, then solve for a:

f(x) = ax² + 2

3 = a(-1²) + 2

3 = a + 2

1 = a

So, a = 1

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2