There are 26 chocolates in a box, all identically shaped. There 3 are filled with nuts, 13 with caramel, and 10 are solid chocolate. You randomly
select one piece, eat it, and then select a second piece. Find the
probability of selecting 2 solid chocolates in a row.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

prime

step-by-step explanation: