Suppose that 10% of people are left handed. If 6 people are selected at random, what is the probability that exactly 2 of them are left handed?

0.0984

Step-by-step explanation:

Given that :

Percentage that are left handed = 10%

P(left handed) = probability of success = 0.1

Number of selection (n) = 6

Number of left hands in selection (x)= exactly 2

P(6, 2) = 6C2 * 0.1^2 * (1 - 0.1)^(6-2)

P(6, 2) = 15 * 0.01 * 0.6561

P(6, 2) = 0.098415

3201

step-by-step explanation:

i dont know sorry

step-by-step explanation: