I NEED HELP I AM STUPID SO I DONT GET THIS HERE IS THE QUISTION 4-x-6(x+5)=15 HE ALSO SAID THIS - Students will determine whether an equation has 0, Infinite, or 1 solution, and if 1, find it. I ADDED A SCREEN SHOT OF QUISTION PLS HELP ME OR I AM FAILING THIS CLASS

im pretty sure it has two real solutions

Step-by-step explanation:

1. simplify the equation given

  (4x - 6)(x + 5) = 15

     4x^2 + 20x - 6x - 30 = 15

        4x^2 + 14x - 45 = 0

2. find the discriminant (b^2 - 4ac); (a = 4, b = 14, c = -45)

  14^2 - (4 x 4 x -45)

     196 - (-720)

        916

  the discriminant is positive, so this equation has 2 real solutions

to find the solutions, factor the bolded equation (if you need help factoring, let me know!)

ik how do do this just give me a few minutes and i will give it to

step-by-step explanation: