Help ASAP, will do brainliest A photo 5 inches wide and 8 inches long is enlarged.
How wide is the new photo if it is (1)12 inches; (2)20 inches; (3)10 inches long?

1) Width is 7.5 inches.

2) Width is 12.5 inches.

3) Width is 6.25 inches.

Step-by-step explanation:

We know that the original photo is 5 inches wide and 8 inches long.

The photo is enlarged by a factor.

1)

The new photo Is 12 inches long.

Since the new length is 12 inches, this means that the scale factor is 12/8 or 3/2.

So, the new width will be 3/2 of the old width. Therefore:

2)

The new photo is 20 inches long.

Since the new length is 20, this means that the scale factor is 20/8 or 5/2.

So, the new width will be 5/2 the old width. Therefore:

3)

The new photo is 10 inches long.

Since the new length is 10, this means that the scale fats is 10/8 or 5/4.

So, the new width will be 5/4 the old width. Therefore:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true