Find the absolute maxima and minima for f(x) on the interval [a, b]. f(x) = 2x3 − 6x2 − 18x − 4, [−10, 10]

Step-by-step explanation:

Given the function

f(x) = 2x3 − 6x2 − 18x − 4 on the interval [-10, 10]

At the end point x = -10

f(-10) = 2(-10)³ − 6(-10)² − 18(-10) − 4

f(-10) = 2(-1000)-6(100)+180-4

f(-10) = -2000-600+176

f(-10) = -1824

At the end point x = 10

f(10) = 2(10)³ − 6(10)² − 18(10) − 4

f(10) = 2(1000)-6(100)-180-4

f(10) = 2000-600-184

f(10) = 1400-184

f(10) = 1216

Hence the absolute minimum is at f(x) = -1824 and maximum is at f(x) = 1216

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.