80% of all ca drivers wear seat belts. if 3 drivers are pulled over, what's the probability that all would be wearing their seat belts? write as a percent to the nearest tenth and explain. thx!

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

i think that you should ask google for the answer to that problem because if we don't know it google does