Jerome is making prizes for a game at the school fair. he has two bags of different pins, one with 15 square pins and one with 20 round pins. every prize will have one of a kind pin. each prize will have the same number of pins. what is the greatest number of pins jerome can put in each prize?

5

Step-by-step explanation:

Given : Jerome is making prizes for a game at the school Fair.

He has two bags of different pins, one with 15 Square pins and one with 20 round pins.

Every prize will have One of a Kind Pin.

Each prize will have the same number of pins.

Then to find the  greatest number of pins Jerome can put in each prize we need to find the greatest common factor of 15 and 20.

Prime factorization of 15 and 20 :-

We can see that the greatest common factor of 15 and 20 =

Hence, the greatest number of pins Jerome can put in each prize = 5

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: