The sum of the ages of three brothers Tema, Juma and Abdul is 65 years. Juma is twice as old as Abdul and a half times as old as Tema. Determine their present age

Tema = 26 years

Juma = 13 years

Abdul = 26 years

Step-by-step explanation:

Let their ages be represented as:

Tema = x

Juma = y

Abdul = z

From the question, we are told that:

Juma is twice as old as Abdul

y = 2z

z = y/2

= 0.5y

And Juma is a half times as old as Tema.

y = 1/2x

y = 0.5x

x = y/0.5

x = 2y

Hence,

x + y + z = 65

2y + y + 2y = 65

= 5y = 65

y = 65/5

y = 13 years

Since y = Zuma's age, Zuma is 13 years old

From the above question

Since 2y = z

y = 13

2 × 13 = z

z = 26

Since z = Abdul's age, Abdul is 26 years old

From the above question

x = 2y

y = 13 years

x = 2 × 13 years

x = 26 years.

Since x = Tema's age

Tema is 26 years.

Therefore, their present ages are:

Tema = 26 years

Juma = 13 years

Abdul = 26 years