Find the difference. 2g/g^2-g-6 - 1/g-3

2g   -      1

g²-g-6     g-3

2g        -  1

(g-3)(g+2)  g-3

take lcm

2g- 1(g+2)

(g-3)(g+2)

g-2

g²-g-6

Step-by-step explanation:

answer: the correct one is a

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.