A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg. How much of each should be added to obtain 60 kg of a mix that will sell for $1.40 per kg?

1. The amount of nuts is _kg and cereal mixture is _ kg to obtain 60 kg of a mix that will sell for $1.40 per kg.

The amount of nuts is 16 kg and cereal mixture is 44 kg to obtain 60 kg of a mix that will sell for $1.40 per kg

Step-by-step explanation:

Let

x=nuts at $2.50 per kg

y=cereal at $1 per kg

x+y=60 kg (1)

2.50x+y=1.40(60) (2)

From (1)

x=60-y

Substitute x=60-y into (2)

2.50x+y=1.40(60)

2.50(60-y)+y=84

150-2.5y+y=84

-1.5y=84-150

-1.5y=-66

Divide both sides by -1.5

y=44 kg

Substitute y=44 into (1)

x+y=60

x+44=60

x=60-44

=16

x=16 kg

can someone answer this question plz

step-by-step explanation:

part d

step-by-step explanation:

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