R is the midpoint of AM. If RA = x2 - 16x and MR = 80, find x.

x = - 4 or x = 20

Step-by-step explanation:

Given R is the midpoint of AM, then

RA = MR , substitute values

x² - 16x = 80 ( subtract 80 from both sides )

x² - 16x - 80 = 0 ← in standard form

(x - 20)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 20 = 0 ⇒ x = 20

x + 4 = 0 ⇒ x = - 4

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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