Juniors and seniors at a local school were surveyed to see if they were left-handed or right-handed. the data is displayed in the table below.

junior senior
left-handed 36 14
right-handed 44 106

if a student is chosen at random from this group, what are the chances of choosing a student who is a left-handed senior?

The chances is 7% that you will pick a left-handed senior. The total is 200, and there are 14. Divide both by 2, and you get 7/100. Therefore, it is 7%.

There are several information's of immense importance that are already provided in the question. Based on those information's the answer can be easily deduced. Let us get down to solving the problem now.
Total number of students in the school = 36 + 14 + 44 + 106
                                                              = 200
Number of left handed senior = 14
Then
Probability of choosing a
 student who is a left-handed senior = 14/200
                                                          = 7/100
                                                          = 7 percent
I hope the procedure is clear for you to understand.

Well if you have 20 bats you probably want 20 balls? you don’t have enough context to answer the question.

For the first question the answer is a, for the second c, for the third d, for the 4th b, for the 5th a