If s(x)=2-x^2 and t(x)=3x, which value is equivalent to (s*t)(-7)?

(s*t)(-7) = 987

Step-by-step explanation:

s(x) = 2 - x²

t(x) = 3x

To find (s*t)(x), multiply s(x) and t(x).

(s*t)(x) = (2 - x²)(3x)

(s*t)(x) = 6x - 3x³

Now that you have (s*t)(x), plug -7 in.

(s*t)(-7) = 6(-7) - 3(-7)³

(s*t)(-7) = 6(-7) - 3(-343)

(s*t)(-7) = -42 + 1029

(s*t)(-7) = 987

answer: it's d

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.