What are the coordinates of the vertex for f(x)= x^2 +6x +13

(-3,4)

Step-by-step explanation:

So we have the quadratic function:

The formula for the x-coordinate of the vertex is:

From the function, we can determine that a is 1, b is 6, and c is 13. Thus:

Multiply:

Divide:

Now, substitute this back into the function to solve for the y-coordinate:

Square and multiply:

Add:

So, the vertex is (-3,4)

And we're done!

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step-by-step explanation:

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