Rewrite the function by completing the square. f(x)=x^{2}+2x+26

x = 4 + √3 and  x = 4 − √3

Step-by-step explanation:

(a−b)^2=a^2−2ab+b2

a^2−b^2=(a−b)(a+b)

−2x^2+16x−26

=−2(1x^2−8x+13)

=−2(x^2−8x+13+3−3)

=−2(x^2−8x+16−3)

=−2(x^2−2(4)x+4^2−3)

=−2((x−4)^2−3)

=−2((x−4)^2−(√3)^2)

=−2((x−4)−√3)((x−4)+√3)

=−2((x−(4+√3)((x−(4−√3))

The zeros of the given algebraic expression are:

−2x^2+16x−26=0

−2((x−(4+√3)((x−(4−√3))=0

x = 4 + √3 and  x = 4 − √3

I strongly suggest using the quadratic formula as this problem is much easier to solve using it.

x = (−b ± ) / 2

answer: the is put the 450

step-by-step explanation: